4029. Elevator Requests IV π
Description
You are given an integer n denoting the number of floors in a building, where the floors are numbered from 0 to n - 1.
You are also given an integer start and a 2D integer array requests, where requests[i] = [arrivali, floori] indicates that a request for floori is made at time arrivali.
At time 0, the elevator is at floor start.
At each second, the elevator may move up by 1 floor, move down by 1 floor, or remain on its current floor.
A request can be fulfilled only at or after its arrival time; it is fulfilled instantly when the elevator is on its requested floor at any time from its arrival time onward.
Return the minimum time needed to fulfill all requests.
Example 1:
Input: n = 9, start = 0, requests = [[0,8],[6,5]]
Output: 9
Explanation:
- Move from floor 0 (
start) to floor 5 (requests[1][1]) in 5 seconds, reaching at time 5. Sincerequests[1][0] = 6, wait until time 6 to fulfill it. - Move from floor 5 to floor 8 (
requests[0][1]) in 3 seconds, fulfilling it at time 9.
Thus, all requests are fulfilled by time 9.
Example 2:
Input: n = 8, start = 5, requests = [[1,7],[7,3]]
Output: 7
Explanation:
- Move from floor 5 (
start) to floor 7 (requests[0][1]) in 2 seconds, reaching at time 2. Sincerequests[0][0] = 1has already passed, floor 7 is fulfilled at time 2. - Move from floor 7 to floor 3 (
requests[1][1]) in 4 seconds, reaching at time 6. Sincerequests[1][0] = 7, wait until time 7.
Thus, all requests are fulfilled by time 7.
Example 3:
Input: n = 7, start = 3, requests = [[0,5],[0,1],[6,3]]
Output: 8
Explanation:
- Move from floor 3 (
start) to floor 5 (requests[0][1]) in 2 seconds, fulfilling it at time 2. - Move from floor 5 to floor 1 (
requests[1][1]) in 4 seconds, fulfilling it at time 6. - Move from floor 1 to floor 3 (
requests[2][1]) in 2 seconds, reaching at time 8. Its request arrived atrequests[2][0] = 6, so floor 3 is fulfilled at time 8.
Thus, all requests are fulfilled by time 8.
Constraints:
1 <= n <= 1091 <= requests.length <= 500requests[i] == [arrivali, floori]0 <= arrivali <= 1090 <= start, floori <= n - 1
Solutions
Solution 1
Thinking
Requests have arrival times and the elevator may wait. \(m\le 500\) rules out a \(2^m\) subset DP. A request is finished at \(\max(\text{time of arrival at that floor},\textit{arrival})\), and we want the moment when the last request is done.
The floors still lie on a line, so an order is a sequence of moves plus mandatory waits. After sorting the requests, an \(O(m^2)\) DP that keeps the processed endpoints (or a processed prefix and the current floor) charges travel and waiting on each transition.
The raw floor indices need not enter the stateβonly distances between requests.
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