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2754. Bind Function to Context πŸ”’

Description

Enhance all functions to have the bindPolyfill method. When bindPolyfill is called with a passed object obj, that object becomes the this context for the function.

For example, if you had the code:

function f() {
  console.log('My context is ' + this.ctx);
}
f();

The output would be "My context is undefined". However, if you bound the function:

function f() {
  console.log('My context is ' + this.ctx);
}
const boundFunc = f.boundPolyfill({ "ctx": "My Object" })
boundFunc();

The output should be "My context is My Object".

You may assume that a single non-null object will be passed to the bindPolyfill method.

Please solve it without the built-in Function.bind method.

 

Example 1:

Input: 
fn = function f(multiplier) { 
  return this.x * multiplier; 
}
obj = {"x": 10}
inputs = [5]
Output: 50
Explanation:
const boundFunc = f.bindPolyfill({"x": 10});
boundFunc(5); // 50
A multiplier of 5 is passed as a parameter.
The context is set to {"x": 10}.
Multiplying those two numbers yields 50.

Example 2:

Input: 
fn = function speak() { 
  return "My name is " + this.name; 
}
obj = {"name": "Kathy"}
inputs = []
Output: "My name is Kathy"
Explanation:
const boundFunc = f.bindPolyfill({"name": "Kathy"});
boundFunc(); // "My name is Kathy"

 

Constraints:

  • obj is a non-null object
  • 0 <= inputs.length <= 100

 

Can you solve it without using any built-in methods?

Solutions

Solution 1

Thinking

Implement \(bind\): the returned function should invoke the original with a given \(this\). A thin wrapper that relies on its own \(this\) would not lock the context.

Install an arrow function on the prototype that \(this.call\)s \(obj\) with the forwarded arguments, so the bound object stays \(obj\).

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type Fn = (...args) => any;

declare global {
    interface Function {
        bindPolyfill(obj: Record<any, any>): Fn;
    }
}

Function.prototype.bindPolyfill = function (obj) {
    return (...args) => {
        return this.call(obj, ...args);
    };
};

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